Verify whether the value of x given in each case are the zeroes of polynomial or not
1.p(x)=2x+1;x=-1/2
2.p(x)=5x- pie ;x=-3/2
3.p(x)=xsq -1;x=+1
4.p(x)=(x-1)(x+2);x=-1,-2
5. p(y)=ysq ;y=0
6.p(x)ax+b;x=-b/a
7.f(x)=3xsq-1;x=-1/root3 ,2/root3
8.f(x)=2x-1,x=1/2,-1/2
Answers
Answered by
2
Answer:
Verify whether the value of x given in each case are the zeroes of polynomial or not
1.p(x)=2x+1;x=-1/2
2.p(x)=5x- pie ;x=-3/2
3.p(x)=xsq -1;x=+1
4.p(x)=(x-1)(x+2);x=-1,-2
5. p(y)=ysq ;y=0
6.p(x)ax+b;x=-b/a
7.f(x)=3xsq-1;x=-1/root3 ,2/root3
8.f(x)=2x-1,x=1/2,-1/2
Answered by
0
Answer:
◇ p(x) = 2 (-1/2) + 1
g(x) = -1/2
-1 + 1 = 0
0 = 0
hence the -1/2 is zero of p(x)
◇ p(x)=5x-pie
g(x)=-3/2
5(-3/2) - 22/7 =0
-15/2 - 22/7 =0
3.14 - 3.14 =0
0=0
◇p(x)= x^2 - 1
g(x)= 1
(1)^2 -1 =0
1-1 =0
0=0
Step-by-step explanation:
PLS MARK ME AS A BRAINLIST
Similar questions