Math, asked by gntkalyan, 1 month ago

Verify whether the value of x given in each case are the zeroes of polynomial or not

1.p(x)=2x+1;x=-1/2

2.p(x)=5x- pie ;x=-3/2

3.p(x)=xsq -1;x=+1

4.p(x)=(x-1)(x+2);x=-1,-2

5. p(y)=ysq ;y=0

6.p(x)ax+b;x=-b/a

7.f(x)=3xsq-1;x=-1/root3 ,2/root3

8.f(x)=2x-1,x=1/2,-1/2​

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Answers

Answered by jgcazares4525
1

Answer:

5.

Step-by-step explanation:

p(5)jyx6b

Answered by shettysachi5
0

Answer:

◇ p(x) = 2 (-1/2) + 1

g(x) = -1/2

-1 + 1 = 0

0 = 0

hence the -1/2 is zero of p(x)

◇ p(x)=5x-pie

g(x)=-3/2

5(-3/2) - 22/7 =0

-15/2 - 22/7 =0

3.14 - 3.14 =0

0=0

◇p(x)= x^2 - 1

g(x)= 1

(1)^2 -1 =0

1-1 =0

0=0

Step-by-step explanation:

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