Question

Verify whether the values of x given in each case are the zeros of the polynomial or not. 1) P(x)=2x+1;x=-1/2 2) p(x)=5x-π;x=-3/2 3) p(x)=x²-1;x=+1 4) p(x)=(x-1)(x+2);x=-1,-2 5) P(y)=y²;y=0 6) p(x)=ax+b;x=-b/a​

Answer 1

Answer:

Step-by-step explanation:

Verify whether the values of x given in each case are the zeros of the polynomial or not.

1 P(x)=2x+1;x=-1/2

P(-1/2) = 2(-1/2) + 1 = -1 + 1 = 0   = 0

2) p(x)=5x-π;x=-3/2

P(-3/2) = 5(-3/2) - π = -15/2 - π  ≠ 0

3) p(x)=x²-1;x=+1

P(1) = 1² - 1 = 1 - 1  = 0  = 0

4) p(x)=(x-1)(x+2);x=-1,-2

P(-1) = (-1-1)(-1 + 2) = (-2)(1) = - 1 ≠ 0

P(-2) = (-2 -1)(-2 + 2) = (-3)(0) = 0 = 0

5) P(y)=y²;y=0

P(0) = 0² = 0 = 0

6) p(x)=ax+b;x=-b/a​

P(-b/a) = a(-b/a) + b = -b + b = 0 = 0

Answer 2

Step-by-step explanation:

I think so these will will help u