verify whether X=-1/✓3,2/✓3 are the zeros of p(X)=3x2-1
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Answer:
P(x) = 3 ( x^2 - 1/3)
= 3 (x - 1/sqrt(3)) (x + 1/sqrt(3))
Roots are + or - 1/sqrt(3).
Qn is to find:
P(- 1/sqrt(3)) = 0 as one factor becomes 0. It's the root.
P(2/sqrt(3)) = 3* (2^2/3) - 1
= 3.
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