Math, asked by ghumansehaj18, 9 months ago

verify whether X=-1/✓3,2/✓3 are the zeros of p(X)=3x2-1​

Answers

Answered by kumarbadshah987
11

Answer:

P(x) = 3 ( x^2 - 1/3)

= 3 (x - 1/sqrt(3)) (x + 1/sqrt(3))

Roots are + or - 1/sqrt(3).

Qn is to find:

P(- 1/sqrt(3)) = 0 as one factor becomes 0. It's the root.

P(2/sqrt(3)) = 3* (2^2/3) - 1

= 3.

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