Question

Verify whether y = 1 is zero of p(y) = y4 -3y2 + 2y +1.

Answer 1

Answer:

NO

Step-by-step explanation:

by putting 1 as Y in the equation we get

1-3*1+2*1+1=1-3+2+1=1

so it will leave the remainder 1

hope it helps

Answer 2

Answer:

y4 - 3y2 + 2y + 1 = p(y)

Step-by-step explanation:

4(1) - 3(1)(2) + 2(1) + 1

4 - 6 + 3

-2 + 3 = 1

No,1 is not zero of p(y) = y4 - 3y2 + 2y +1.