Question

Verify which of the following sets of
numbers represent a Pythagorean triplet.
a) 6, 8, 10
b) 9, 40, 41
c) 12, 35, 36

Answer 1

Answer:

1. Let6,8,and 10 be the sides of triangle.

Then,we know that,

AB² +BC² = AC²

$\sqrt{ \: } {8}^{2} + \sqrt{ \: \: \:} 6 {}^{2} = ac$

$\sqrt{64 + 36} = ac$

AC=10units

Hence,Thegiven numbers are pythagoreantriplet.

2. ∴ 41² = 40²+9²

41² +9² =1600 + 81 =1681

41² = 1681

∴ 1681 =1681

Hence these length are Pythagorean triples.