verify with numbers 72 and 36 that the sum of a number and the number obtained by reversing its digits is always divisible by 11
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proved
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verify with numbers 72 and 36 that the sum of a number and the number obtained by reversing its digits is always divisible by 11
We can do it and verify the same.
So the sum of a two digit number and the number formed by reversing its digits is exactly divisible by 11 and the quotient got is the sum of the digits of the original number. So adding both the numbers we get
72 = 72 + 27 = 99, which is exactly divisible by 11
36 = 36 + 63 = 99, which is exactly divisible by 11.
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