Verify with numbers 72 and 36 that the sum of a number and the number obtained by reversing its digits is always divisible by 11
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Verify with numbers 72 and 36 that the sum of a number and the number obtained by reversing its digits is always divisible by 11
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Answer:
72+36=108 it is divisible by 3
by reversing order number obtained is
(36 multiply by 10) +76
=360+72=432
it is also divisible by 9
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