Question

Verify x = -1 and 2 are the zeroes of the polynomial p(x) = (x+1)(x-2)​

Answer 1

ANSWER: (x+1)(x-2) a=1 b=-1 c= -2 = x(x-2) +1(x-2) =x^2-2x+1(x-2) =x^2-2x+x-2=x^2 -x-2 x+1 =0 Or x-2 =0x=-1 x= 2 so; alpha = -1 beta = 2 alpha + beta Or alpha • beta = -1+2 = 1 = -1 × 2 = -2 verified: alpha + beta = - b/a = - ( -1)/ 1 = 1 alpha • beta = c/a = -2