verify x^3-y^3=(x-y)(x^2+xy+y^2)
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We know that,
(x - y)³ = x³ - y³ - 3xy(x - y)
Hence,
x³ - y³ = (x - y)³ + 3xy(x - y)
Take out x - y as common factor
→ x³ - y³ = (x - y)[(x - y)² + 3xy]
We know that,
(x - y)² = x² + y² - 2xy
Hence,
→ x³ - y³ = (x - y)(x² + y²- 2xy + 3xy)
→ x³ - y³ = (x - y)(x² + y² + xy)
Hence, verified.
Alternative Method:-
Let x = 2, y = 1
→ x³ - y³ = (x - y)(x² + y² + xy)
→ (2)³ - (1)³ = (2 - 1)[(2)² + (1)² + 2(1)]
→ 8 - 1 = (1)(4 + 1 + 2)
→ 7 = (1)(7)
→ 7 = 7
Hence, verified.
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