verify : (x-y) 2 = x2 - 2xy +y2 for x =4, Y =1
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Answered by
2
Step-by-step explanation:
(4-1)2=4×2-2×4×1+1×2
6=8-8+2
6=2
8
Answered by
2
Given,
x = 4, y = 1
LHS= (x-y)^2
=(4-1)^2
=3^2
=9
RHS= x^2-2xy+y^2
=4^2-2.4.1+1^2
=16-8+1
=9
Therefore,
(x-y)^2=x^2-2xy+y^2
verified
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