verify x (y+z)=x y+x Z for x=1/3,y= 1/2 and z=-1/8
Answers
given that :
x=1/3, y=1/2, z=-1/8
verify: x(y+z)=xy+xz
verification: 1.
x(y+z)= 1/3 [1/2+(-1/8)]
= 1/3 [1/2-1/8]
= 1/3 {4-1/8] {l.c.m= 8}
= 1/3 * 3/8
= 1/8 {both the 3"s get cancelled as one is in the numerator and the other is in the denominator}
2. xy+xz=1/3*1/2 + 1/3*-1/8
=1/6-1/24
= 4-1/24 {l.c.m= 24}
= 3/24
=1/8
therfore, x(y+z)=xy+xz
, hence proved.
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