Question

verify x+(y+z)=(x+y)+zby taking the valuex=1/4, y=1/5 z=1/6
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Answer 1

Step-by-step explanation:

$we \: have \: to \: verify \: x + (y + z) = (x + y) + z \: \\ and \: we \: know \: the \: value \: of \: \\ x = \frac{1}{4} \\ y = \frac{1}{5} \\ z = \frac{1}{6} \\ on \: putting \: the \: value \: \\ \frac{1}{4} + ( \frac{1}{5} + \frac{1}{6} ) = ( \frac{1}{4} + \frac{1}{5} ) + \frac{1}{6} \\ on \: taking \: lcm \\ \frac{1}{4} + \frac{6 + 5}{30} = \frac{5 + 4}{20} + \frac{1}{6} \\ \frac{15 + 22}{60} = \frac{27 + 10}{60} \\ \frac{37}{60} = \frac{37}{60}$

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Answer 2

Answer:

1/20

Step-by-step explanation:

$x + (y + z) = (x + y) + s \\ x + (x + y) - z = ( x + y) \\ 2x + y - z= (x + y) \\ 2x + y - z - (x + y) \\ 2x + y - z - x - y \\ 2x - x - z \\ x - z$