Physics, asked by BHAWESHGUNJIYAL, 11 months ago

Vernier calliper has 1mm marked on the main scale it has 20 equal division on the vernier scale which match with 16 main scale division find its least count

Answers

Answered by 2345Dj
3

Answer:

Explanation:

Least count means smallest length that can be measured using an instrument.

A vernier callipers has two scales:

1. The main scale

2.The vernier scale.

Now we know that Least count = 1 main scale division - 1 vernier scale division

Generally in a vernier callipers N main scale divisions coincide with N-1 vernier scale divisions.

But acc to our question,

20 VSD coincides with 16 MSD

Therefore, Least Count = 1 MSD - 1VSD = 1mm - (16/20)*1mm = 4/20 mm = 0.2mm that is option D.

Hence the Least Count of the Vernier Callipers is 0.2 mm

Answered by fhibahiqbal
1

Here,

20 Vernier scale divisions= 16 main scale divisions.

20 V.S.D=16 mm

1 V.S.D=16/20 mm=0.8mm

Least count of Vernier Caliper=

Value of one Main scale division - Value of one V.S.D

Therefore Least Count= 1mm - 0.8mm

= 0.2mm

Hope this helps!

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