Question

vernier scale with 10 divisions slides over a main scale who's pitch is 0.5 mm ( pitch is = 1 MSD) if a bob of diameter 9.75 mm is held between the Jaws, determine the MSR and VCD if a)there is no zero error. b) the zero error equals to 0.35 mm

Answer 1

Answer:

Least count of a screw gauge can be defined as the smallest value that can be measured by the screw gauge. Least can be defined as the ratio of the pitch of the screw gauge to the number of divisions in the circular scale. Pitch of the screw gauge is 1mm and the number of divisions in the circular scale is 100.