Question

Vertex A (4, –5) and point of intersection O (–6, 7) of diagonals of rhombus ABCD are given, then find the coordinates of vertex C

Answer 1

Answer:

C = ( -16 , 19)

Step-by-step explanation:

in a rhombus Diagonal Perpendicularly bisect each other

now AC is a diagonal

O ( - 6 , 7) is point of intersection of diagonals

=> O is mid point of A & C

A = ( 4 , - 5)    C = (x , y)

O = (A + C)/2

-6 = (4 + x)/2  => -12 = 4 + x  => x = -16

7 = ( -5 + y)/2 => 14 = -5 + y => y = 19

the coordinates of vertex C = ( -16 , 19)