vertex of parabola y^2=4y - 4x is
vivek2001:
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y^2=4y - 4x
=>y²=4(x-y)
=>y²+4y+4=4x-4
=>(y+2)²=4(x-1) which is the form of Y²=4aX
where X=x-1 and Y=y-2 and 4a=4,therefore a=1
For the vertex,
X=0,Y=0 i.e.,x+1=0,or x=1 and y-2=0,or y=2
Therefore coordinates of vertex are (1,2)
=>y²=4(x-y)
=>y²+4y+4=4x-4
=>(y+2)²=4(x-1) which is the form of Y²=4aX
where X=x-1 and Y=y-2 and 4a=4,therefore a=1
For the vertex,
X=0,Y=0 i.e.,x+1=0,or x=1 and y-2=0,or y=2
Therefore coordinates of vertex are (1,2)
sory bro.......your options are a.(1,2) b.(2,1) c.(0,0) d.(-1,-2)
see i've corrected
is it right now
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