Question

Vertical angle of an isosceles triangle is 15 degree more than each of its base angle find each angle of the triangle

Answer 1

HEY THERE ..!!

HERE IS YOURS SOLUTION;

◆ Let the base angle be x°.

So, according to the given question;

x = base angle

x + 15 = verticle angle

We know that Iso. ∆ has is two sides equal;


=> x = x must be the opposite angle of the sides equal.

◆ Now, we use angle sum property to find x;

x + x + x + 15 = 180°

=> 3x = 165°

=> x = 55°

So, x = 55° & x + 15 = 55° + 15 = 70° = verticle angle.

★So, base angles are 55° , 55° & 70°★

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Answer 2

Answer:

55°, 55°, 70°

Step-by-step explanation:

Let The Base Angles Be x°

Therefore,

x + 15°= vertical angle

Therefore

x =x must be the opposite Angles of the sides equal as it is an isosceles Triangle which has 2 sides equal

° ° ATP

°

x+x+(x+15)=180

=> x+x+x =180-15

=> 3x = 165

=> x = 165/3

=> x =55°

° x+15= vertical Angles =(55+15)° = 70°

° °

ANS:- THE ANGLES MEASURES 55°,55°, and 70°

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