vertical angle of Iscoceles triangle is 64° find base angles
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Let the isosceles triangle be ABC.
/_BAC = 64° and /_ABC and /_BCA are base angles
Let the angle ABC and BCA be x
•°• x + x + 64° = 180°
2x + 64° = 180°
2x = 180° - 64° = 116°
x = 116°/2 = 58°
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