Question

vertical pole 20 metres long cast a shadow 20 root 3 long find the sun's altitude at the same time at our cost is Shadow 90 metres long determine the height of the tower​

Answer 1

I am going to answer it with a picture

Answer 2

Step-by-step explanation:

Given vertical pole 20 metres long cast a shadow 20 root 3 long find the sun's altitude at the same time at our cost is Shadow 90 metres long determine the height of the tower

• Let the height of the vertical building be m
• So for both the buildings the angle of elevation is same.
• now we have two triangles ABC and PQR
• In triangle ABC
• So height AB = 20 m, base BC = 20√3 m
• In triangle PQR
• So height PQ = m, base QR = 90 m
• Now tan theta = AB/BC
•                         = 20 / 20√3
•                        = 1/√3-------------1
• Also tan theta = PQ / QR
•                        = m/90----------2
• So from 1 and 2 we have
•                     1/√3 = m/90
•                        √3 m = 90
•                  Or m = 90 / √3
• Rationalising the denominator we get
•                      m = 90 / √3 x √3/√3
•                    m = 90 √3 / 3
•                  Or m = 30 √3 m

Reference link will be

https://brainly.in/question/5913378