Question

vertical pole is 300 metres high. The angle subtended by the pole at a point 300√3 meter from base​

Answer 1

Step-by-step explanation:

Let height of the small tower be x

DB = CE = x

ED = CB = 120

AD = AB - DB = 300 - x

In ΔAED

tan 60° = AD/ED

√3 = (300 - x)/120

⇒ x = 300 - 120√3 = 92.15