Vertical Throw - Physics
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Question :
A baseball is hit straight up into the air with a speed of about 20m/s.
(a) How high does it go?
(b) How long is it in the air?
Given :
Initial velocity of the ball = 20m/s
To Find :
Maximum height attained by the ball and tine taken to reach there.
Solution :
❖ For a body thrown vertically upward, g is taken negative.
Since constant acceleration due to gravity acts on the ball throughout the motion, equation of kinematics can be applied to solve this question
♦ Maximum height :
Applying third equation of kinematics,
➠ v² - u² = 2gH
➠ 0² - 20² = 2(-10) × H
➠ -400 = -20H
➠ H = 400/20
➠ H = 20 m
♦ Time of ascent :
Applying first equation of kinematics,
➠ v = u + gt
➠ 0 = 20 + (-10)t
➠ -20 = -10t
➠ t = 2 s
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