vertices of the square are inscribed in a circle of radius 8cm find the area of the square
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Answered by
5
radius =8cm diameter = 2*8=16cm . Then let side of square be X so a/q Xsq + Xsq =16 sq so Xsq =128 cm sq.
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Answered by
1
Answer:
radius =8
therefore dia=16
Step-by-step explanation:
now by pgt
(16)^2=ab^2+bc^2
here ab=bc (adjacent sides of a triangle)
256=2ab^2
256/2=ab^2
128=ab^2
ab=root128
ab=2root34
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