Vertices of triangle ABC are A(4,6) B(1,5) C(7,2) DE intersect sides AB & AC at D & E such that AD/AB=AE/AC=1/3.Calculate the area of triangle ADE & compare it with area of triangle ABC
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✨His Answer is wrong. But the method is correct
The ar(ΔABC) -is not 9÷2
it is 15/2
and the ar(ΔADE) IS 5/6
∴THE RATIO IS 1/9✨
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