Question

vertices of triangle are given by i+3j+2k and 2i-j+k and -i+2j+3k then area of triangle is
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Answer 1

Answer:

Step-by-step explanation:

Let OA=i+3j+2k=(1,3,2)

OB=2i-j+k=(2,-1,1)

OC=-i+2j+3k=(-1,2,3)

AB=OB-OA=(1,-4,-1)

AC=OC-OA=(-2,-1,1)

AB*AC=-5i+j-9k

Arwa of triangle=1/2 [AB*AC]

1/2[$\sqrt{107}$] square units