Question

Vertices of triangles are (a;c+a) (a;c) (-a;c-a).Find the area
Pls solve this as fast as possible

Answer 1

Answer:

area of triangle =1/2(X1(y2-y3)+X2(y3-y1)+X3(y1-y2)

given,

(a,a+c), (a,c) ,(-a,c-a)

area of triangle =1/2(a(c-c+a))+a(c-a-a-c)+(-a)(a+c-c)

1/2(a(a)+a(-2a)-a(a))

=-a2

a2sq.units

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Answer 2

Answer:

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