Question

vertify that 2 and -3 are the zeros of the polynomials p(x)= x²+x-6​

Answer 1

Step-by-step explanation:

okay

first of all we substitute 2 as x

p(2) = 2² +2 -6

p(2) = 4 + 2 -6

p(2) = 0

Verified

then we substitute -3 as x

p(-3) = (-3)² +(-3) -6

p(-3) = 9 -3 -6

p(-3) = 9-9

p(-3) = 0

verified

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