Question

Vertix of triangle ABC
A(3, -2) B(0, 6) C(-2, 4)

Answer 1

Answer:

$1 \div 2 {x1 (y2 - y3) + x2(y3 - y1) + x3(y1 - y2)}$

Step-by-step explanation:

1/2{ (3 (6-4)+0 (4+2)+(-2)(-2-6)}

1/2{3×2 + 0×6 (-2) × (-8)}

1/2 × 22

11 square unit

Answer 2

Solution

Step-by-step explanation:

Area of triangle = $\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

so, we have to implement the following values in the formula.

Then,                     $\frac{1}{2}[3(6-4)+0(4+2)-2(-2-6)]$

                              $\frac{1}{2}[3(2)+0(6)-2(-8)]$

                              $\frac{1}{2}[6+0+16]$

                              $\frac{1}{2} \times 22$ = 11

$\therefore$ the area of the triangle is 11 unit.

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