Question

Very Confusing Question

Answer 1

Step-by-step explanation:

WE VAN DO IT BY MANY WAYS

1ST WAY

SA IS A DIAGONAL

DIAGONAL OF A SAUARE DIVIDES TUE ANGLE EQUALLY.

ANGLE IN A SQUARE IS 90.

SO THE DIAGONAL DIVIDES AS 45° AND 45°

NIW WE TAKE ∆SON

THEY HAVE GIVEN ONE ANGLE OF THE TRIANGLE

AND WE ALSO KNOW THE OTHER ANGLE OF THE TRIANGLE THAT IS 45 (BY THAT DIAGONAL)

BY USING THE ANGLES IN A TRIANGLE SUM UP TO MAKE 180°

WE CAN FIND ANGLE SNO

ANGLE NOS+ANGLE NSO+ANGLE NOS=180°

80°+45°+ANGLE NSO=180°

NAGKE NSO=180°-125°

NSO=55°

ANGLE NSO AND ANGLE X ARE CORRESPONDING ANGLES.

AND WE KNOW THAT CORRESPONDING ANGLES OF A TRIANGLE ARE SUPPLEMENTARY THAT IS 180°

THEREFORE

ANGLE NSO+ANGLE X=180°

ANGLE X=180°-55°=125°

WE CAN FIND IT ALSO IN ANOTHER SIMPLE WAY

THAT IS BY USING EXTERIOR ANGLE SUM PROPERTY

THIS STATES THAT THE EXTERIOR ANGLE OF A TRIANGLE IS EQUAL TO THE SUM OF TWO OPPOITE INTERIOR ANGLES.

FOR ∆AOB THE ANGLE X IS A EXTERIOR ANGLE.

ANGLE OAB AND ANGLE O ARE THE INTERIOR OPPOSITE ANGLES.

ANGLE O = 80° (BECUASE ALTERNATE ANGLES ARE EQUAL)

ANGLE OAB = 45(WE FOUND OUT IT THE DIAGONAL)

SO,

ANGLE O+ANGLE OAB=X

80°+45°=X

X°=125°

THEREFORE THE X°=125°