Question

Very easy class 9 question​

Answer 1

Step-by-step explanation:

$In\:\triangle ABC, \\</p><p> \angle ABC+ \angle ACB+\angle BAC=180\degree\\(By\:angle\:sum\:property\:of\:a\:\triangle) \\\\</p><p>\therefore 57\degree+ 53\degree+\angle BAC=180\degree\\\\</p><p>\therefore 110\degree+\angle BAC=180\degree\\\\</p><p>\therefore \angle BAC=180\degree-110\degree\\\\</p><p>\therefore \angle BAC=70\degree\\\\</p><p>\because \angle BDC= \angle BAC\\(Angles\: subtended \:by\:same\:segment) \\\\</p><p> \huge\purple {\boxed {\therefore {\angle BDC=70\degree}}}$