very fast pls solve this question
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7×(a+6d)=11×(a+10d),
7a+42d=11a+110d,
then
0=11a-7a+110d-42d,
4a+68d=0,
then it becomes
a+17d=0=18th term,
therefore 18th term of this A.P will be zero
7×(a+6d)=11×(a+10d),
7a+42d=11a+110d,
then
0=11a-7a+110d-42d,
4a+68d=0,
then it becomes
a+17d=0=18th term,
therefore 18th term of this A.P will be zero
nani2204:
can u say me how 4a+68d=0 becomes a+17d=18th term
tq
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