very fast solution I have to do
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F=ma
F=100N
m=20kg
a=?
F =ma
100=20 ×a
a=100÷20
=4m/s sq.
if the mass of the box is doubled then
m=20× 2=40kg
100=40×a
a=100÷40
=2.5m/s sq.
2)
distance travelled =change in velocity×time
S=u+v/2 ×t ......1
first equation of motion=v=u+at ......2
putting 2 in 1
S=u+u+at/2 ×t
S=2u/2 + at/2
S=u+ at/2 ×t
S=ut +1/2 at^2
3) v^2=u^2+2aS
F=ma
F=100N
m=20kg
a=?
F =ma
100=20 ×a
a=100÷20
=4m/s sq.
if the mass of the box is doubled then
m=20× 2=40kg
100=40×a
a=100÷40
=2.5m/s sq.
2)
distance travelled =change in velocity×time
S=u+v/2 ×t ......1
first equation of motion=v=u+at ......2
putting 2 in 1
S=u+u+at/2 ×t
S=2u/2 + at/2
S=u+ at/2 ×t
S=ut +1/2 at^2
3) v^2=u^2+2aS
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