CBSE BOARD X, asked by za6715, 1 year ago

very short answer type question

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Answered by disha11100

Hey mate!

here is your answer:

We will first find the resistance of both the bulbs by using the formula P=V^2/R :

Bulb 1 :

Resistance 1= V^2/R=807ohm

Bulb 2 :

Resistance2=484ohm

When we connect them in series , the current :

I = V*R

R=807+484=1291

so, I = 220(1291)=0.17 ampere (approx.)

Now, Voltage of first bulb =I/P=23.3 watt

Voltage of second bulb=I/P=14 watt

Since, Voltage of 60 W is more so, it will glow more brighter.

HOPE IT HELPED YOU^_^

disha11100: the bulb which has more resistance or the more voltage is brighter

disha11100: I am a little confused now , give some time I will just recheck it on Google and let u know

disha11100: The bulb which has a higher resistance has more voltage and hence has more brightness

disha11100: since in series we have different voltage we need to find it in the question

saifali16: thanks frnd

za6715: So is it correct

disha11100: yes it is correct ^_^

disha11100: since it is very short , you can solve it till resistance

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