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you Answer is 3
GIVEN : Prime factorization of a natural number n is 2³ × 3⁴ × 5⁴ × 7
SOLUTION :
n = 2³ × 3⁴ × 5⁴ × 7
n = 2³ × 3⁴ × 5³ × 5 × 7
n = (2³ × 5³) × 3⁴ × 5 × 7
n = (2 × 5)³ × 3⁴ × 5 × 7
n = 10³ × 3⁴ × 5 × 7
Hence, the number of consecutive zeros in n, is 3 (three)
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