Question

very simple question sum of the digits of the two digit number is 9.the number is obtained by interchanging the digits exceeds the given number by 27.find the given number.plz this question fast.....

Answer 1

Hi Bro,

Let the two digit number be xy.
The given number be 10x+y. If we reverse it, the number would be 10y+x.
By 1st condition,
x+y=9
x + y - 9 = 0. (1)
By 2nd condition,
10y+x = 10x+y+27
10x - x - 10y + y + 27 =0
9x - 9y+27 =0.
÷9 implies that, x - y + 3 =0. (2)
By (1), x = 9-y. (3)

Sub (3) in (2),
9-y-y+3=0
12 - 2y = 0
-2y = -12
y = 6

Substitute y = 6 in (3),
x = 9 - 6
x = 3

Since the given two digit number is 36.

By your friend Aditya.