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For her school science project Shreya performed an experiment in science lab. She prepared a report where she got different values of freezing points of some gases and her report was characterized into two categories that was degree Celsius and degree Fahrenheit. The given table shows the freezing points in (°F) of different gases at sea level.

Answer 1

Answer:

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$\begin{gathered}\begin{gathered}\begin{gathered}\large\boxed{ \begin{array}{cc}\large\sf\dag \: {\underline{Gas- \: Sea\: level\:at\:c}} \\ \\ \:\:\:\:\:\:\:\:\bigstar \: \sf{Hydrogen=-259.44°}\\ \\\:\:\:\:\:\:\bigstar \:\sf{Krypton=-157.22 °} \\ \\ \:\:\:\bigstar \: \sf{Oxygen =−222.77°} \\ \\ \:\bigstar \sf{Helium=-272.22°} \\ \\ \bigstar \: \sf{Argon=-189.44°}\end{array} }\end{gathered}\end{gathered}\end{gathered}$

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Answer 2

Given :   Shreya performed an experiment in science lab

She prepared a report where she got different values of freezing points of some gases and her report was characterized into two categories that was degree Celsius and degree Fahrenheit.

Gases  Freezing point at sea level(°F)  Freezing point at sea level(°C)

Hydrogen    -435

Krypton        -251

Oxygen     -369

Helium      -458

Argon        -309​

To find :   list the gases in decreasing order according to their freezing point at sea level.  

Convert each into (°C ) using the relation. C=5/9 ( F-32).  

Which one of the gas has lowest temperature.

Solution :

gases in decreasing order according to their freezing point at sea level.

-251  , -309  , - 369 , -435 , - 458

=> Krypton  , Argon , oxygen  ,  Hydrogen , Helium

Convert each into ( °C ) using the relation. C=5/9 ( F-32).  

                  °F           °C

Hydrogen -435 -259.44

Krypton -251      -157.22

Oxygen -369 -222.78

Helium -458 -272.22

Argon -309 -189.44

lowest temperature.  Helium -458 °F    or  -272.22°C

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