Question

Very Urgent Please Help​

Answer 1

Answer:

75°

Step-by-step explanation:

AB = CD,

so, OP = OQ,

So, ΔPOQ is a isoceles triangle

So, ∠QPO = ∠PQO

So, ∠QPO + ∠PQO + ∠POQ = 180°(sum of internal angles in a triangle)

2∠QPO +150° = 180°

2∠QPO = 30°

∠QPO = 15°

So, ∠QPO + ∠OPB + ∠APQ = 180°

15° + 90° + ∠APQ = 180°

∠APQ = 180° - 15° - 90°

∠APQ = 75°

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