Question

very urgent plz 37 plz plz

Answer 1

<ADC = <BCD ...(1) (angles of square, each 90°)
<CDE = <DCE ..(2)(angle of equilateral triangle)

on adding (1) and (2)
<ADC + <CDE = <BCD + <DCE
<ADE = <BCE

In triangle ADE and BCE
AD = BC (sides of square)
<ADE = <BCE (proved above)
DE = CE (sides of equilateral triangle)

'triangle ADE' is congruent to 'triangle BCE'
by SAS congruency rule

Answer 2

I hope this will help you