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<ADC = <BCD ...(1) (angles of square, each 90°)
<CDE = <DCE ..(2)(angle of equilateral triangle)
on adding (1) and (2)
<ADC + <CDE = <BCD + <DCE
<ADE = <BCE
In triangle ADE and BCE
AD = BC (sides of square)
<ADE = <BCE (proved above)
DE = CE (sides of equilateral triangle)
'triangle ADE' is congruent to 'triangle BCE'
by SAS congruency rule
<CDE = <DCE ..(2)(angle of equilateral triangle)
on adding (1) and (2)
<ADC + <CDE = <BCD + <DCE
<ADE = <BCE
In triangle ADE and BCE
AD = BC (sides of square)
<ADE = <BCE (proved above)
DE = CE (sides of equilateral triangle)
'triangle ADE' is congruent to 'triangle BCE'
by SAS congruency rule
SakshaM725:
if it helps mark it brainliest
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I hope this will help you
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