Question

Very urgent
Plz solve by factorization: a square x square - ( A square B square + 1) X + b square is equal to 0.

Answer 1

${a}^{2} {x}^{2} - ( {a}^{2} {b}^{2} + 1)x + {b}^{2} = 0 \\ {a}^{2} {x}^{2} - {a}^{2} {b}^{2}x - x + {b}^{2} = 0 \\ {a}^{2} x(x - {b}^{2}) - 1(x - {b}^{2}) = 0 \\ ( {a}^{2} x - 1)(x - {b}^{2} ) = 0 \\ are \: the \: factors. \: \\for \: roots \\ ( {a}^{2} x - 1) = 0 \\ x = \frac{1}{ {a}^{2} } \\ (x - {b}^{2} ) = 0 \\ x = {b}^{2}$