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ρ = 1.295 kg/m³
decrease in the pressure of air = ρ g h = 1.295 * g * 107 Pa
ρ g h = 13.6 * 10³ * g * H
H = decrease in barometric height of mercury
= ρ g h / (13.6*10³ * g) = 10.188 mm
pressure on mercury column in barometer = weight of air column /area of cross section row * g * h of air = row * g * H of mercury H of mercury = air density * height of air / density of mercury.
Hope this helped.
decrease in the pressure of air = ρ g h = 1.295 * g * 107 Pa
ρ g h = 13.6 * 10³ * g * H
H = decrease in barometric height of mercury
= ρ g h / (13.6*10³ * g) = 10.188 mm
pressure on mercury column in barometer = weight of air column /area of cross section row * g * h of air = row * g * H of mercury H of mercury = air density * height of air / density of mercury.
Hope this helped.
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