Question

vessel contains water upto height of 1.5 metre taking the density of water thousand kilogram per metre cube and acceleration due to gravity 9.8 square second square calculate the pressure exerted by the water at the bottom of the vessel and also if find if area of cross section of base of vessel is 100 cm square calculate the thrust​

Answer 1

Pressure =ρgh

where ρ=density of water

g=acceleration due to gravity

P=10 3 ×9.8×1.5=1.47×10 4 Nm 2

Upthrust = Force exerted = Pressure \times Area

⇒Upthrust=1.47×10 4 Nm 2 ×100×10 −4 m=147N

Answer 2

$\bold{(a) \: Pressure} \\ \bold{Height = 1.5m} \\ \bold{Density = 1000 kg/m³} \\ \bold{Acceleration \: due \: to \: gravity \: = \: 9.8m/s²} \\ \bold \green{Pressure \: = \: hpg} \\ \bold{ = \: 1.5 \times 1000 \times 9.8} \\ \bold{ = \: 14700 Pa} \\ \bold \red{ = \: 1.47 \times {10}^{4} N/m² \: \: ....ans}$

$\bold{(b) \: Thrust \: at \: the \: base \: of \: vessel} \\ \bold{Pressure \: = \: \frac{force}{area} } \\ \bold \green{force \: = \: Pressure \times area} \\ \bold{ = \: 1.47 \times {10}^{4} \times 100} \\ \bold \red{ = \: 147 N \: \: ....ans}$

Hope it helps you...

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