Math, asked by atul337, 1 year ago

vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?

Answers

Answered by SD8

Here is your answer.... ......

Attachments:

SD8: Then we find how much portion of the mixture is left syrup - simple subtraction

SD8: water you need to subtract and add y as according to the question we are replacing the mixture with y litres water.

SD8: remaing quantities of the mixture are same

SD8: half water and half syrup

SD8: so new ratio =1:1

SD8: then the equation is already in the picture I ppsted

SD8: *posted*

SD8: And th shorcut is

SD8: remaining quantity of syrup and water in the mixture , both will be half of the mixture.

SD8: so that way the other equation is formed

Answered by hiteshgyanchandani6

Suppose the vessel initially contains 8 liters of liquid.

Let x liters of this liquid be replaced with water.

Water in new mixture = (3-3x/8+x)

Syrup in new mixture = (5-5x/8)

Then (3-3x/8+x) = (5-5x/8)

5x + 24 = 40 - 5x

10x=16

==>x=8/5

So part of mixture replaced is 8/5*1/8=1/5

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