vessel is filled with liquid, 3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
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9
Here is your answer.... ......
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Then we find how much portion of the mixture is left syrup - simple subtraction
water you need to subtract and add y as according to the question we are replacing the mixture with y litres water.
remaing quantities of the mixture are same
half water and half syrup
so new ratio =1:1
then the equation is already in the picture I ppsted
*posted*
And th shorcut is
remaining quantity of syrup and water in the mixture , both will be half of the mixture.
so that way the other equation is formed
Answered by
2
Suppose the vessel initially contains 8 liters of liquid.
Let x liters of this liquid be replaced with water.
Water in new mixture = (3-3x/8+x)
Syrup in new mixture = (5-5x/8)
Then (3-3x/8+x) = (5-5x/8)
5x + 24 = 40 - 5x
10x=16
==>x=8/5
So part of mixture replaced is 8/5*1/8=1/5
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