Question

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10. A can do a piece of work in 80 days. He works at it for 10 days and then B alone finishes the
remaining work in 42 days. In how many days could both do it?
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Answer 1

Step-by-step explanation:

ANSWER

A's 1 days' work =

80

1

A's 10 days' work =

80

10

=

8

1

Remaining work =1−

8

1

=

8

7

8

7

of the work is completed by B in 42 days

∴ The whole work is completed by B in

7

42×8

days = 48 days

∴ B's 1 days' work =

48

1

(A + B)'s 1 days' work =

80

1

+

48

1

=

240

3+5

=

240

8

=

30

1

∴ A and B can complete the whole work together in 30 days

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