Question

VH1:6 Tal2: 9. What is the ratio of the distance between Bhoomika and top of the gate to the distance between the top of the gate and building? (a)1:5 (b)1:6 (c) 2:5​

Answer 1

Answer:

From the diagram, PB=CD=12 m

AP=AB−PB=(22−12) m=10 m

Also CP=BD=24 m

Since △APC is a right angled triangle,

AC

2

=AP

2

+PC

2

AC

2

=10

2

+24

2

AC

2

=676

∴AC=2:5 m

Hence, distance between their tops is 2:5 m.

Step-by-step explanation:

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