(vi) 10x - 1 = 3, x=0
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10x - 1/x - 3 = 0
=> 10x^2 - 1 - 3x = 0
=> 10x^2 - 3x - 1 = 0
=> 10x^2 - 5x + 2x - 1 = 0
=> 5x ( 2x - 1) + 1 (2x - 1) = 0
=> (5x + 1) ( 2x - 1) = 0
Now, either (5x +1) = 0 Or (2x-1) = 0
=> x = -1/5 Or x = 1/2
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