(vi) [-15 +{4+ (-1)-(3)} x 6] using the BDMAS rule, find the values
Answers
Answer:
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15−(−3){4−(7−3)}÷3[{5+(−3)×(−6)}]=
23
5
Step-by-step explanation:
Given : Expression 15-(-3)\{4-(7-3)\}\div 3[\{5+(-3)\times(-6)\}]15−(−3){4−(7−3)}÷3[{5+(−3)×(−6)}]
To find : Simplify the expression ?
Solution :
Using BODMAS,
Solving the expression,
=15+3\{4-4\}\div 3[\{5-3\times(-6)\}]=15+3{4−4}÷3[{5−3×(−6)}]
=15+3\{0\}\div 3[\{5+18\}]=15+3{0}÷3[{5+18}]
=15+0\div 3[23]=15+0÷3[23]
=15\div 69=15÷69
=\frac{15}{69}=
69
15
=\frac{5}{23}=
23
5
Therefore, 15-(-3)\{4-(7-3)\}\div 3[\{5+(-3)\times(-6)\}]=\frac{5}{23}15−(−3){4−(7−3)}÷3[{5+(−3)×(−6)}]=
23
5
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