Math, asked by deorajydv555, 8 months ago

(vi) 3a3a + 2c) - 4b(b + c)
(viii) 3x2 - 2 - 22 - 2xy - 2y7 - 22
2 - 12 - 1 + 2ر2= (x)
(xii) 12 - 8 + 2​

Answers

Answered by chellurivaibhav
5

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Answered by csingh296parihar
0

Answer:

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