Question

(vi) [(3x2 – 4y2) – (3y2 – 2z2) – (4z2 – 2X2)]​

Answer 1

Answer:

$(3 {x}^{2} - 4 {y}^{2} ) - (3 {y}^{2} - 2 {z}^{2} ) - (4 {z}^{2} - 2 {x}^{2} ) \\ \\ 3 {x}^{2} - 4 {y}^{2} - 3 {y}^{2} + 2 {z}^{2} - 4 {z}^{2} + 2 {x}^{2} \\ \\ 5 {x}^{2} - 7 {y}^{2} - 2 {z}^{2}$

Answer 2

Answer:

( 3x^2 - 4y^2)-(3y^2-2z^2) -(4z^2 -2x^2)

3x^2 - 4y^2 -3y^2 + 2z^2 - 4z^2 + 2x^2

5x^2 - 7y^2 - 2z^2