(vi) 3x²-x-4 find the zeros of the polynomial
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P(x) = 3x^2 - x - 4
=> 3x^2 -4x-3x-4
=> x(3x-4) -1(3x-4)
=> (3x-4) (x-1)
=> x= 4/3 or x= 1
Therefore alpha = 4/3 & beeta = 1
=> 3x^2 -4x-3x-4
=> x(3x-4) -1(3x-4)
=> (3x-4) (x-1)
=> x= 4/3 or x= 1
Therefore alpha = 4/3 & beeta = 1
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