(vi) 3x² - x - 4
sum of zeros and product of zero
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Answer:
3x^2-x-4=0
3x^2-(4-3)x-4=0
3x^2-4x+3x-4=0
x(3x-4)+1(3x-4)=0
(3x-4) (x+1)=0
either, 3x-4=0
x=4/3
or,. x+1=0
x=-1
sum of zeros=4/3+(-1)
4/3-1
(4-3)/3
1/3
product of zeros=(4/3)×(-1)
-4/3
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